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If `|[cos(A+B), -sin(A+B), cos2B], [sinA, cosA, sinB], [-cosA, sinA, cosB]|=0`, then B=

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If `|[cos(A+B), -sin(A+B), cos2B], [sinA, cosA, sinB], [-cosA, sinA, cosB]|=0`, then B=
A. `npi, ninZ`
B. `2npi, ninZ`
C. `(2npm1)(pi)/(2), ninZ`
D. `(2npipm1)pi, ninZ`
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Correct Answer - C
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