The cartesian equation of a line is ` 3x + 1 = 6 y - 2 = 1 -z`.
Find the vector equation of the line.
A. `(hati + hatj -hatk) + lambda(2hati + hatj - hatk)`
B. `(-hati + hatj + hatk)+ lambda(2hati + hatj - hatk)`
C. `(1/3hati + 1/6hatj - hatk) +lambda(2hati + hatj - 6hatk)`
D. `(-1/3hati + 1/3hatj +hatk) + lambda(2hati + hatj - 6hatk)`
