Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
36 views
in Mathematics by (123k points)
The cartesian equation of a line is 3x - 1 = 6y + 2 = 1 - z . Find the vector equation of the line .
A. `(-1/3hati + 1/3hati +hatk) +lambda(2hati + hatj - 6hatk)`
B. `(1/3hati - 1/3hatj + hatk) + lambda(2hati +hatj - 6hatk)`
C. `(hati + 2hatj + hatk) +lambda(2hati + hatj - 6hatk)`
D. `(hati - 2hatj - hatk) + lambda(2hati + hatj - 6hatk)`

Please log in or register to answer this question.

1 Answer

0 votes
by (122k points)
Correct Answer - B

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...