Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
72 views
in Physics by (122k points)
When a current carrying coil is placed in a uniform magnetic field of induction `B`, then a torque `tau` acts on it. If `I` is the current, `n` is the number of turns and `A` is the face area of the coil and the normal to the coil makes an angle `theta` with `B`, Then
A. `tau= n I AB`
B. `tau= n I AB cos theta`
C. `tau = n I AB sin theta`
D. `tau = n I AB tan theta`

Please log in or register to answer this question.

1 Answer

0 votes
by (122k points)
Correct Answer - C

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...