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calculate the degree of hydrolysis of 0.1M solution of sodium acetate in water at 250C, Ka for CH3COOH is 1.8x10-5,Kw=1x10-14

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The degree of hydrolysis(h) of salt of weak acid and strong base is related with Kw Ka and c by above relation

So

h = [10^-14/(5,74x10^-5x0.1)]^0.5=1.32x10^-4

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