Question

The floor of a building consists of3 000 tiles which are rhombus shaped. The diagonals of each of the tiles are 45 cm and 30 cm. Find the total cost of polishing the floor, if cost per m² is Rs.2.50.

Answer 1

Diagonals of each (shape / rhombus) tiles

d₁ = 45cm, d₂ = 30cm

Total tiles = 3000

Total area = 3000 × Area of each tile = 3000 × 1/2 × d₁ × d₂

= 3000 x 1/2 × 45 × 30 = 2025000 cm²

= \(\frac {2025000}{100\times 100}\) m² = 202.5m²

∴ Cost of polishing the floor at the rate of Rs. 2.50 per a square metre 202.5 × 2.50 

= Rs. 506.25