Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
5.5k views
in Chemistry by (87.4k points)

Lead iodate , Pb(IO3)2 , is a slightly soluble salt with a Ksp of 2.6x10–13 at 25°C. To 35.0 mL of 0.150 Pb(NO3)2 solution is added 15.0 mL of 0.800 M KIO3. A precipitate of Pb(IO3)2 results. What are the [Pb2+] and [IO3 ] in the final solution?

1 Answer

+2 votes
by (77.4k points)
selected by
 
Best answer

Using bounce-back method, first assume all Pb2+ reacts with all IO3 ion to produce Pb(IO3)2, and then some of the precipitate dissolves back to the ions.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...