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in Chemistry by (87.4k points)

A hydrocarbon with five carbon atoms in the molecule, decolourizes alkaline KMnO4, but does not give a precipitate with ammonical Cu2Cl2 solution. The hydrocarbon is possibly

a. 1-pentyne 

b. 1, 3-pentadiyne 

c. 2-pentyne 

d. 1, 4-pentadiyne

1 Answer

+1 vote
by (77.5k points)
selected by
 
Best answer

Correct option (C) 2-pentyne 

Explanation:

It is 2-pentyne, CH3C ≡ CCH2CH3, 

which being a non-terminal alkyne, will not give ppt. with ammonical Cu2Cl2 solution.

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