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The no of ways in which 10 persons can go in two cars so that there may be 5 in each car, supposing that two particular persons

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The no of ways in which 10 persons can go in two cars so that there may be 5 in each car, supposing that two particular persons will not go in the same car is:

(a) 1/2(10C5)

(b) 1/2(8C5)

(c) 2(8C4)

(d) 8C4

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1 Answer

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Best answer

Correct option: (c) 2(8C4)

Explanation:

arrangements of 8 persons so that there are 4 persons in each car = 8C4

arrangements of two particular persons = 2

∴ Total ways = 2 x 8C4

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