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In the expansion of `(e^(7x)+e^(3x))/(e^(5x))` the constant term is

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Answer:
We have
`(e^(7x)+e^(3x))/(e^(5x))=e^(2x)+e^(-2x)=2(1+(2x)^(2)/(2!)+(2x)^(4)/(4!)+….)`
`therefore` constant term =2

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