Answer:
we have
`1+(1)/(4.2!)+(1)/(16.4!)+(1)/(64.6!)…to infty`
=`1+(1)/(2!)(1/2)^(2)+(1)/(4!)(1/2)^(4)+(1)/(6!)(1/2)^(6)+… to infty`
`=(e^(1//2)+e^(-1//2))/(2)`
before `[(e^(x)+e^(-x))/(2)=1+(x^(2))/(2!)+(x^(4))/(4!)+(x^(6))/(6!)+…]`
`=(e+1)/2sqrt(e )`