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If `y=-{x^(3)+(x^(6))/(2)+(x^(9))/(3)+….}` then
A. `x^(3)=1-e^(y)`
B. `x=log_(e )(1+y)`
C. `x^(3)=e^(y)`
D. `x=1+e^(y)`

1 Answer

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Best answer
Answer:
We have
`y=x^(3)+(x^(3))^(2)/(2)(x^(3))^(3)/(3)`+…
`rarr y=log_(e)(1-x^(3))rarre^(y)=1-x^(3)=1-e^(y)`

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