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The intensity ratio of two waves is `9:1`. If they produce interference, the ratio of maximum to minimum intensity will be
A. `1:9`
B. `9:1`
C. `1:4`
D. `4:1`

1 Answer

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Answer:
`(I_(1))/(I_(2))=9/1`
`I_(max)/I_(min)=[(sqrt(I_(1)/I_(2))+1)/(sqrt(I_(1)/I_(2))-1)]^(2)`
`[sqrt(9+1)/(sqrt(9)-1)]^(2) rArr(I_(max))/(I_(min))=4^2/2^2=4/1`

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