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0 votes
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in Mathematics by (71.3k points)

The no, of ways in which ten candidates A1,A2...A10 can be ranked, if A1 is always above A2 is _______

(a) 2.8! 

(b) 9! 

(c) 10! 

(d) 5.9!

1 Answer

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Best answer

Correct option: (d) 5.9!

Explanation:

Number of ways to rank 10 candidates = 10!

In this half ranks a1 is always above a2 and in remolding half ranks a2 is always above a1 

∴ required number of ranks = 10!/2 = 5 x 9!

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