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in Determinants by (74.0k points)
If `a ne b ne c`, then solution of equation
`|{:(x-a,x-b,x-c),(x-b,x-c,x-a),(x-c, x-a,x-a):}|=0" "is:`
A. `x=0`
B. `x=a+b+c`
C. `x=1/2(a+b+c)(d) x=1/3(a+b+c)`
D. `x=1/3(a+b+c)`

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1 Answer

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by (73.8k points)
Correct Answer - D

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