Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
86 views
in Physics by (74.8k points)
The real angle of dip, if a magnet is suspended at an angle of `30^(@)` to the magnetic meridian and the dip needle makes an angle of `45^(@)` with horizontal, is:
A. `tan^(-1)(sqrt(3)/(2))`
B. `tan^(-1)(sqrt(3))`
C. `tan^(-1)((sqrt(3))/(sqrt(2)))`
D. `tan^(-1)((2)/(sqrt(3)))`

Please log in or register to answer this question.

1 Answer

0 votes
by (74.1k points)
Correct Answer - A

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...