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in Chemistry by (74.0k points)
An electron in a hydrogen like atom makes transition from a state in which itd de Broglie wavelength is `lambda_(1)` to a state where its de Broglie wavelength is `lambda_(2)` then wavelength of photon (`lambda`) generated will be :
A. `lambda=lambda_(1)-lambda_(2)`
B. `lambda=(4mc)/(h){(lambda_(1)^(2)lambda_(2)^(2))/(lambda_(1)^(2)-lambda_(2)^(2))}`
C. `lambda=sqrt((lambda_(1)^(2)lambda_(2)^(2))/(lambda_(1)^(2)-lambda_(2)^(2)))`
D. `lambda=(2mc)/(h){(lambda_(1)^(2)lambda_(2)^(2))/(lambda_(1)^(2)-lambda_(2)^(2))}`

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1 Answer

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by (73.8k points)
Correct Answer - D

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