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in Chemistry by (74.0k points)
Hydrogen atom:
The electronic ground state of hydrogen atom contains one electron in the first orbit. If sufficient energy is provided, this electron can be promoted to higher energy levels. The electronic energy of a hydrogen-like species (any atom//ions with nuclear charge Z and one electron) can be given as
`E_(n)=-(R_(H)Z^(2))/(n^(2))` where `R_(H)= "Rydberg constant," n= "principal quantum number"`
A gaseous excited hydrogen-like species with nuclear charge Z can emit radiations of six different photon energies.
(a) The principal quantum number of the excited state is :
(b) It was observed that when this excited species emits photons of energy`=2.64 eV` when it comes to next lower energy state. Calculate the nuclear charge of the species.
The least energy required to remove an electron from a species is know as the ionization energy (I.E.) of the species. The experimental I.E. of He atom is `24.58 eV`.
A. `6`
B. `5`
C. `4`
D. `3`

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1 Answer

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by (73.8k points)
Correct Answer - (a) `4` (b) `2`

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