Compound X one treatment with HI give Y, Y on treatment with ethanolic KOH gives Z (an isomer of X). Ozonolysis of Z (with `H_2O_2` workup) gives a two -carbon carboxylic acid and four carbon ketone . Hence, X is :
A. 2-methyl-2-pentene
B. 4-methyl-1-pentene
C. 2,3-dimethyl-2-butene
D. 3-methyl-1-pentene