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in Physics by (74.0k points)
A cylindrical conductor has length `l` and area of cross section A. Its conductivity changes with distance `(x)` from one of its ends as `sigma = sigma_(0) (l)/(x). [sigma_(0) "is a constant"]`. Calculate electric field inside the conductor as a function of `x`, when a cell of emf V is connected across the ends.
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A. The electric resistance of cylinder along its axis is `l/(2sigma_(0)A)`
B. The electric current in the wire will be `(V_(0)sigma_(0)A)/(2l)`
C. The electric current in the wire will be `(2V_(0)sigma_(0))/(l)`
D. The electric field in the wire at x in xylinder will be `(2V_(0))/l^(2)x`

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1 Answer

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by (73.8k points)
Correct Answer - A::C::D

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