A.5 V battery with internal resistance `2 Omega` and a 2 V battery with internal resistance `1Omega` are connected to a `10 Omega` resistor as shown in the figure.
The current in the `10 Omega` resistor is -
A. `0.03 A P_(1)" to "P_(2)`
B. `0.03" A "P_(2)" to "P_(1)`
C. `0.27" A "P_(1)" to "P_(2)`
D. `0.27" A "P_(2)" to "P_(1)`