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in Physics by (74.0k points)
In a large building, there are 15 bulbs of 40 W, 5 bulbs of 100 W, 5 fans of 80 W and 1 heater of 1 kW. The voltage of electric mains is 220 V. The minimum capacity fo the main fuse of the building will be :
A. `8 A`
B. `10 A`
C. `12 A`
D. `14 A`

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2 Answers

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Correct Answer - C
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Total power of all the devices 

\(=[15\times40+5\times100+5\times80+1\times1000]W=2500 W\)

\(\therefore\) Current \(=\frac{2500 W}{220 V}=11.36 A \approx12A.\)

\(\therefore\) Minimum capacity of the main fuse should be 12 A.

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