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+1 vote
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in Chemistry by (74.9k points)
Correct set of four quantum numbers for the valence (outermost) electron of rubidium `(Z = 37)` is
A. `5,0,0,+1/2`
B. `5,1,0,+1/2`
C. `5,1,1,+1/2`
D. `6,0,0,+1/2`

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2 Answers

0 votes
by (74.1k points)
Correct Answer - A
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by (48.2k points)

Correct option is (A) \(5, 0, 0, +\frac12\) 

electric configuration of Rb(37) \(=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1\)

valence electron in 5s orbital.

\(\therefore\) Quantum number are- \(n = 5, l = 0, m = 0 ,s = +\frac12\).

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