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in Binomial Theorem by (74.8k points)
If sin `theta ` and - cos `theta ` are the roots of the equation `ax^2-bx-c=0` where a, b and c the side of a triangle ABC , then cos B is equal to :-
A. `1-(c )/(2a)`
B. `1-(c )/(a)`
C. `1+( c)/(2a)`
D. `1+ (c )/(3a)`

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1 Answer

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by (74.1k points)
Correct Answer - C

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