Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.1k views
in Chemistry by (59.7k points)

The expression of the solubility product constant Ksp for Fe(OH)2:

А.   Ksp = [Fe2+]⋅2[OH]

B.   Ksp = [Fe2+]+2[OH]

C.   Ksp = [Fe]⋅[OH]2

D.   Ksp = [Fe2+]⋅[OH]2

E.   Ksp = [Fe2+]⋅[OH

1 Answer

+1 vote
by (88.9k points)
selected by
 
Best answer

D.  Ksp = [Fe2+]⋅[OH

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...