The oxidation number of \( P t \) in the complex \( \left[ Pt \left( C _{2} H _{4}\right) Cl _{3}\right] \) is 1) \( +1 \) 2) \( +2 \) 3) \( +3 \) 4) \( +4 \)

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kushal0711 · Answer 1 · 2022-04-22T14:54:38+0000

Oxidation no of pt will be +3

C2 will be -2 in each carbon

H4 will bhi +1 in each carbon

Cl3 will bhi -1 in each carbon

Pt -4 +4-3=0

Pt=3