Given : A = 0.12 m2 ; T = 527 + 273 = 800 K
(i) The total rate of energy emission, Eb :
Eb = σ AT4 W (watts) ...
= 5.67 × 10–8 × 0.12 × (800)4 = 5.67 × 0.12 × \(\left(\cfrac{800}{100}\right)^4\) = 2786.9 W.
(ii) The intensity of normal radiation, Ibn :
Ibn = Eb/π , where Eb is in W/m2 K4
(iii) The wavelength of maximum monochromatic emissive power, λmax :
From Wien’s displacement law,