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The value of the expression [ sec(75° - θ) - cosec (15° + θ) - tan(55° - θ) + cot (35° + θ) ]  is equal to (A) 3/2 

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The value of the expression [ sec(75°- θ) - cosec (15°+ θ) - tan(55°- θ) + cot (35°+ θ) ]  is equal to

(A) 3/2 

(B) 0 

(C) –1 

(D) 1

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1 Answer

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by (43.6k points)

Correct answer is (B) 0

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