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Ouestion 4 In the given figure, \( A O B \) and \( C O D \) are diameters of a circle with centre \( O \). If angle \( OBD =40^{\circ} \), find the measure of angle CAO.

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40% only 
please say the ans

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In Δ OAC & OBD

OC = OD (Radii)

OA = OB (Radii)

∠AOC = ∠BOD (Vertically opposite angles)

\(\therefore\) Δ OAC ≅ Δ OBD (By SAS congruence criteria)

\(\therefore\) ∠ CAP = ∠ OBD (By C.P.C.T.)

\(\therefore\) ∠CAO = 40° (\(\because ∠OBD=40^{\circ}given\))

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