Correct option is (B) Transitive and reflexive
qRp ⇔ q is a factor of p.
Since, every term (number/algebraic term) is a factor of itself.
\(\therefore\) Relation R is a reflexive relation.
Since, 2 is a factor of 6
But 6 is not a factor of 2.
It means 2 Rg but symmetric.
Let qRp and pRr
It means q is a factor of p
⇒ p = mq
and p is a factor of r
⇒ r = np
⇒ r = n(mq) = nmq
⇒ q is a factor of r.
\(\therefore\) Relation R is transitive relation.