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in Sets, relations and functions by (476 points)

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Correct option is (B) Transitive and reflexive

qRp ⇔ q is a factor of p.

Since, every term (number/algebraic term) is a factor of itself.

\(\therefore\) Relation R is a reflexive relation.

Since, 2 is a factor of 6

But 6 is not a factor of 2.

It means 2 Rg but symmetric.

Let qRp and pRr

It means q is a factor of p

⇒ p = mq

and p is a factor of r

⇒ r = np

⇒ r = n(mq) = nmq

⇒ q is a factor of r.

\(\therefore\) Relation R is transitive relation.

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