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18.2k views
in CBSE by (35 points)

pls answer with full explanation....

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2 Answers

+1 vote
by (35 points)

(i) solution 

According to question

Width of sidewalk is x m

Inner length of pool is (12- 2x) m

Inner beadth of pool (7-2x) m

Area of pool is 36 sq. m

Area of pool =length × breadth

36= (12-2x) ×(7-2x)

36 = 84 - 24x -14x +4x^2

36= 84 -38x +4x^2

4x^2 -38x +48 = 0

2x^2 -19x + 24 = 0 is the required quadratic equation

(ii) solution

As we solve the above equation we will find the width of the sidewalk

2(2x^2 - 19x +24) = 0

2x^2 -19- + 24 = 0

2x^2 - 16x -3x +24 = 0

2x(x-8) -3(x-8) =0

(2x-3)(x-8) = 0

X = 3/2 or 8

Width of sidewalk = 8m is not possible

Hence, width of sidewalk is 3/2 m

I hope you will understand properly

                             THANK YOU

by (35 points)
Thanks helped alot..
0 votes
by (35 points)
edited by
1) 2x^ 2 -19x +24 = 0

Is the required quadratic equation

2) And with of the sidewalk is 3/2 m

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