(i) solution
According to question
Width of sidewalk is x m
Inner length of pool is (12- 2x) m
Inner beadth of pool (7-2x) m
Area of pool is 36 sq. m
Area of pool =length × breadth
36= (12-2x) ×(7-2x)
36 = 84 - 24x -14x +4x^2
36= 84 -38x +4x^2
4x^2 -38x +48 = 0
2x^2 -19x + 24 = 0 is the required quadratic equation
(ii) solution
As we solve the above equation we will find the width of the sidewalk
2(2x^2 - 19x +24) = 0
2x^2 -19- + 24 = 0
2x^2 - 16x -3x +24 = 0
2x(x-8) -3(x-8) =0
(2x-3)(x-8) = 0
X = 3/2 or 8
Width of sidewalk = 8m is not possible
Hence, width of sidewalk is 3/2 m
I hope you will understand properly
THANK YOU