Let E be the events of selecting first horse .Given that P(E)=1/5 and Let F be the events of selecting 2ND horse .Given that P(F)= 2/3
THEREFORE P(EC)=4/5 , P(FC)= 1/3
(I)BOTH WILL BE SELECTED
P(E and F)= P(EF)=P(E)P(F)= 2/5*1/3=2/15
(ii) ONLY ONE OF THEM WILL BE SELECTED
P(EC F)+P(FCE)= P(EC)P(F)+P(FC)P(E)=4/5*2/3+1/3*1/5 =9/15=3/5
(iii) NONE OF THEM WILL BE SELECTED= P(ECFC) = P(EC ) P(FC) = 4/5 *1/3 = 4/15
(IV) ATLEAST ONE OF THEM SELECTED= = 1-4/15 = 11/15