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If A+B=90º and tan A=3/4, what is cot B?

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If A+B=90º and tan A=3/4, what is cot B?
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Solution is...........


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A+B =90°
⇒A= 90°-B

tanA = 3/4
⇒tan(90°-B) = 3/4

∵ tan(90°-A) = cotA

∴ tan(90°-B) = 3/4
⇒cotB = 3/4

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If tan A=cotB, prove that A + B = 90º .
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