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+1 vote
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in Matrices by (20 points)

A= [ (2 −6) (-1  3)]  find B2x2≠ ∅ and B2x2≠Identity such that A and B commute

   

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1 Answer

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A = \(\begin{bmatrix}2&-6\\-1&3\end{bmatrix}\)

Let B = \(\begin{bmatrix}1&6\\1&0\end{bmatrix}\)

Then AB  = \(\begin{bmatrix}2&-6\\-1&3\end{bmatrix}\) \(\begin{bmatrix}1&6\\1&0\end{bmatrix}\)

 = \(\begin{bmatrix}-4&12\\2&-6\end{bmatrix}\)

BA = \(\begin{bmatrix}1&6\\1&0\end{bmatrix}\) \(\begin{bmatrix}2&-6\\-1&3\end{bmatrix}\)

 = \(\begin{bmatrix}-4&12\\2&-6\end{bmatrix}\)

\(\therefore\) AB = BA, where B = \(\begin{bmatrix}1&6\\1&0\end{bmatrix}\) \(\neq\) O, I

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