Question

There is a 2% error in the determination of G. If E is assumed to be correctly determined, what will be the error in the calculation of Poisson’s ratio when its correct value is 0.2?

Answer 1

We know E = 2G(1 + m)  

Applying the principle of differential calculus, we can differentiate above equation keeping in mind that \(\delta\)E = 0, because E is constant.

0 = 2\(\delta\)G (1 + m) +2G\(\delta\)v

 \(\delta\)v = \(\frac{\delta G}{G}(1+m)\)

% error will be