Cross sectional Area of column = 300 × 300 = 90000mm2
Area of steel bars As = 10 × (\(\pi\)/4)(20)2 = 3141.59mm2
Area of concrete = 90000 – 3141.59 = 86858.4 mm2
Each component (concrete and steel bars) shorten by the same amount under the compressive load, and therefore
Strain in concrete = strain in steel
\(\sigma\)c/Ec = \(\sigma\)s/Es
Where \(\sigma\)c, \(\sigma\)s are stress induced in concrete and steel respectively
\(\sigma\)s = (Es \(\sigma\)c)/Ec
= (200 × 109 /15 × 109 ) \(\sigma\)c = 13.33 \(\sigma\)c
Further,
Total load on column = Load carried by steel + load carried by concrete
P = \(\sigma\)s.As + \(\sigma\)c.Ac
450 × 103 = 13.33\(\sigma\)c × 3141.59 + \(\sigma\)c. 86858.4
= 128735.8 \(\sigma\)c
\(\sigma\)c = 3.59 N/mm2
\(\sigma\)s = 13.33 × 3.59 = 46.95 N/mm2
Load carried by concrete Pc = \(\sigma\)cAc = 3.59 × 86858.4 = 311821.656 N = 311.82KN
Load carried by steel Ps = \(\sigma\)sAs = 46.95 × 3141.59 = 147497.65 N = 147.49 KN