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What is the concentration of aluminium in 3.0 M aluminium sulphate?

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Al2(SO4)3 → 2Al+3 +\( 3 SOH_4^{-2}\)

3M Al2(SO4)3 means, 3 mole of Al2(SO4)3 per litre of solution.

From above equation we see that 1 mole of Al2(SO4)3 gives 2 mole of Al+3 in solution.

∴ 3 mole Al2(SO4)3 per litre of solution produce = 6 mol Al+3 per litre.

Therefore, The concentration of Al+3 will be 6 M

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