Al2(SO4)3 → 2Al+3 +\( 3 SOH_4^{-2}\)
3M Al2(SO4)3 means, 3 mole of Al2(SO4)3 per litre of solution.
From above equation we see that 1 mole of Al2(SO4)3 gives 2 mole of Al+3 in solution.
∴ 3 mole Al2(SO4)3 per litre of solution produce = 6 mol Al+3 per litre.
Therefore, The concentration of Al+3 will be 6 M
