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in Binomial Theorem by (45 points)

The coefficient of x^2 in the expansion of the product (2 - x^2)· ((1 + 2x + 3x^2)^6 + (1 - 4x^2)^6) is

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Let a=((1+2x+3x2)6+(1−4x2)6)

∴ Coefficient of x2 in the expansion of the product (2−x)2((1+2x+3x2)6+(1−4x2)6)

    =2( Coefficient of x2 in a)−1(Constant of expansion)

In the expansion of ((1+2x+3x2)6+(1−4x2)6), 

Constant =1+1=2

Coefficient of x2= Coefficient of x2 in (6C0​(1+2x)6(3x2)0)+ Coefficient of x2 in (6C1​(1+2x)53)−6C1​(4)

=6C2​4+6×3−24

=6=+18−24=54

Then, coefficient of x2 in (2−x)2((1+2x+3x2)6+(1−4x2)6)

=2×54−1(2)=108−2=106

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