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0 votes
3.3k views
in Kinematics by (29 points)
edited by

The ceiling of a long hall is 80 m high. What is the maximum horizontal distance that a ball thrown with a speed of 50 m/s can go without hitting the ceiling of the hall?

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1 Answer

+1 vote
by (44.0k points)

Correct option is (1) 240 m

H = \(\frac{(u sin\theta)^2}{2g}\) 

80 = \(\frac{u^2sin^2\theta}{2g}\)

\(\frac{80\times2\times10}{2540}=sin^2\theta\)

16/25 = sin2θ 

4/5 = sin θ

R = \(\frac{u^2sin2\theta}g\)

R = \(\frac{2500\times2sin\theta cos\theta}g\)

R = \(\cfrac{2500\times2\times\frac45\times35}{10}\)

R = 240 m

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