Laplace transform $y^{\prime \prime}+\lambda^{2} y=\sin \lambda t ;$ with $y(0)=1, y\left(\frac{\pi}{2 \lambda}\right)=\pi$

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Solve the differential equation using Laplace transform

$y^{\prime \prime}+\lambda^{2} y=\sin \lambda t ;$ with $y(0)=1, y\left(\frac{\pi}{2 \lambda}\right)=\pi$