The self inductance of a coil having 400 turns is \( 10 mH \). The magnetic flux through the cross section of the coil corresponding to current \( 2 mA \) is
(a) \( 4 \times 10^{-5} Wb \)
(b) \( 2 \times 10^{-3} Wb \)
(c) \( 3 \times 10^{-5} Wb \)
(d) \( 8 \times 10^{-3} Wb \)