A = \(\begin{bmatrix}1&2\\3&1\end{bmatrix}\) B = \(\begin{bmatrix}2&1\\3&2\end{bmatrix},\) C = \(\begin{bmatrix}1&2&3\\3&1&0\end{bmatrix}\)
AB = \(\begin{bmatrix}8&5\\9&5\end{bmatrix}\)
(AB)C = \(\begin{bmatrix}23&21&24\\24&23&27\end{bmatrix}\)
BC = \(\begin{bmatrix}5&5&6\\9&8&9\end{bmatrix}\)
A(BC) = \(\begin{bmatrix}23&21&24\\24&23&27\end{bmatrix}\)
Hence (AB) C = A(BC)
Hence verified.