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in Linear Equations by (20 points)
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\[ \begin{array}{l} 3 x+y+1=0 \\ 2 x-3 y+8=0 \end{array} \] \( \rightarrow \) 

Shade the triangle formed aborg witt \( x-a x i s \) \( \Rightarrow \) find its area

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1 Answer

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3x + y + 1 = 0

2x - 3y + 8 = 0

To draw 3x + y + 1 = 0, we have

x 0 -1/3 -1
y -1 0 2

To draw 2x  - 3y + 8 = 0, we have

x 0 -4 -1
y 8/3 0 2

Area = 1/2 x Base x Height

 = 1/2 x 11/3 x 2

 = 11/3 square units

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