A = \(\begin{bmatrix}-1&1&1\\1&-1&1\\1&1&-1\end{bmatrix}\)
|A| = -1 + 1 + 1 + 1 + 1 + 1 = 4
Now,
|2 adj (3adj(4A-1))| = 23|adj(3adj (4A-1))|
(\(\because\) |KA| = Kn|A|)
= 23|3adj(4A-1)|2 (\(\because\) |adj A| = |A|n-1)
= 23(33|adj (4A-1)|)2 (\(\because\) |KA| = Kn|A|)
= 23.36 |adj(4A-1)|4
= 23.36(43. (A-1))4 (\(\because\) |KA| = Kn|A|)
= 23.36(43. \(\frac14\)) (\(\because\) |A-1| = \(\frac1{|A|}=\frac14\))
= 23.36(42)4
= 23.36.48
= 23.36.216
= 219.36
\(\therefore\) a = 19, b = 6
\(\therefore\) a - 2b = 19 - 12 = 7