The odds in favour: The ratio of the number of ways that an outcome can occur compared to how many ways it cannot occur.
Given that getting a blue token are 1 : 2.
\(\therefore\) x + 2x = 6
⇒ x = 2
Hence, there is 2 blue tokens out of 6 tokens.
Also, 5y + y = 6
⇒ y = 1
Hence, there is 1 red token out of 6 tokens.
\(\therefore\) There is 3 black tokens out of 6 given tokens.
(b) odd against getting a black taken = 3/3 = 1 = 1 : 1