Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
156 views
in Sets, relations and functions by (15 points)
81. Which of the following is not correct for relation \( R \) on the set of real numbers? [JEE(Main)-2021] (1) \( (x, y) \in R \Leftrightarrow|x-y| \leq 1 \) is reflexive and symmetric. (2) \( (x, y) \in R \Leftrightarrow 0|x|-|y| \leq 1 \) is neither transitive nor symmetric (3) \( (x, y) \in R \Leftrightarrow 0<|x-y| \leq 1 \) is symmetric and transitive (4) \( (x, y) \in R \Leftrightarrow|x|-|y| \leq 1 \) is reflexive but not symmetric

Please log in or register to answer this question.

1 Answer

0 votes
by (24.8k points)

Answer: (x, y) ∈ R \(\Leftrightarrow\) 0 < |x – y|\(\leq\) 1 is symmetric and transitive.

Note that (1,2) and (2,3) satisfy 0 < |x – y| \(\leq\)1 but (1,3) does not satisfy it so

0 \(\leq\) |x – y| \(\leq\) 1 is symmetric but not transitive

So, (2) is correct.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...