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0 votes
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in Physics by (37.5k points)

When a conductor of capacitance C is charged to potential V, the total amount of energy present in the field is :

(A) \(\cfrac{1}{2}CV\)

(B) \(\cfrac{1}{2}C^2V\)

(C) \(\cfrac{1}{2}CV^2\)

(D) CV \(\)

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1 Answer

+1 vote
by (39.7k points)

 Correct option is (C) \(\cfrac{1}{2}CV^2\)

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