\(\lim\limits_{n\to\infty}(1+\frac1n)^{pn+q}\) (1\(\infty\) type)
= Exp{\(\lim\limits_{n\to\infty}(1+\frac1n-1)^{pn+q}\)}
= Exp {\(\lim\limits_{n\to\infty}\frac{pn+q}n\)}
= Exp{\(\lim\limits_{n\to\infty}(p+\frac qn)\)}
= Exp {P}
= ExpP
∴ \(\lim\limits_{n\to\infty}(1+\frac 1n)^{pn+q}\) = eP