# A question from light chapter 10 class

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An object 5 cm high is placed at a distance of 30 cm from a convex lens of a focal length 15 cm . Find the position and nature

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Given:-

Height of Object, Ho = 5cm

Distance of the Object, u = -30cm

Focal length , f = +15cm

Now,

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$

$\frac{1}{v} = \frac{1}{f} + \frac{1}{u}$

$\frac{1}{v} = \frac{1}{15} - \frac{1}{30} = \frac{1}{30}$

$v = 30cm$

(i) The image is formed at a distance of 30cm from the lens to its right side.

(ii) Magnification, m = $\frac{v}{u} = \frac{30}{-30}$ $= -1$

The image formed is real, inverted and of the same size as that of object.